Physics, asked by ambresahil33, 8 months ago

Calculate the rise of water inside a
clean glass capillary tube of radius
0.1 mm, when immersed in water of
surface tension 7 x 10^-2 N/m. The angle
of contact between water and glass is
zero, density of water =
1000 kg/m^3, g
= 9.8 m/s.​

Answers

Answered by iamsuk1986
3

Answer:The height h through which a liquid will rise in a capillary tube of radius r  is given by

h=  

rρg

2Scosθ

​  

, where S is the surface tension, ρ is the density of the liquid and θ is the angle of contact.

⇒h=  

(0.2×10  

−3

)×10  

3

×10

2×7.2×10  

−2

×1

​  

=7.2×10  

−2

m=7.2cm≈7cm

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