Calculate the rise of water inside a
clean glass capillary tube of radius
0.1 mm, when immersed in water of
surface tension 7 x 10^-2 N/m. The angle
of contact between water and glass is
zero, density of water =
1000 kg/m^3, g
= 9.8 m/s.
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Answered by
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Answer:The height h through which a liquid will rise in a capillary tube of radius r is given by
h=
rρg
2Scosθ
, where S is the surface tension, ρ is the density of the liquid and θ is the angle of contact.
⇒h=
(0.2×10
−3
)×10
3
×10
2×7.2×10
−2
×1
=7.2×10
−2
m=7.2cm≈7cm
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