Physics, asked by aisaaisha, 11 months ago

calculate The RMS speed of an ideal diatomic gas having molecular weight 32 gram per mole at zero degree celsius at the specific heat at constant pressure and volume are respectively 8.3 J per mole kelvin and 6.34cal per mol kelvin​

Answers

Answered by ranjanalok961
2

Answer:

In given question it seems like the units of Cp and Cv are incorrect, Because for an ideal gas the difference of Cp and Cv

is R, irrespective of the atomicity of gas.

Explanation:

RMS speed = ( 3RT/M)½= [ (3×8.3×273) /(32/100)]½=))(212786. 43) ½=461.2 m/s

Similar questions