calculate The RMS speed of Nitrogen molecule for 27Celsius
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Root mean square = √3RT/M
R = 8.314 J/K/mole
T = 27 + 273
= 300 K
molecular mas of N₂=M= 28 X 10⁻³ kg
put these values in the formula
RMS = √( 3 x 8.314 x 300/28 X 10⁻³)
= √(267,235.714)
= 516.94 m/s
R = 8.314 J/K/mole
T = 27 + 273
= 300 K
molecular mas of N₂=M= 28 X 10⁻³ kg
put these values in the formula
RMS = √( 3 x 8.314 x 300/28 X 10⁻³)
= √(267,235.714)
= 516.94 m/s
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Explanation:
Upon heating, it loses its water molecule from the coordination sphere. There is a transition of electrons from t2g to eg orbital. The splitting of the d-orbital takes place. ... Therefore, when [Ti(H₂O)₆]³⁺ is heated, the color changes from violet to colorless.
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