Question

Calculate the rms speed of nitrogen molecules at 27 degrees Celsius

Answer 1

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Answer 2

The rms speed of nitrogen molecules at 27 degrees Celsius is 516.9 m/s

Explanation:

The formula used for root mean square speed is:

$\nu_{rms}=\sqrt{\frac{3RT}{M}}$

where, = root mean square speed

R = gas constant  = 8.314 J/Kmol

T = temperature = $27^0C=(27+273)K=300K$

M = atomic mass of nitrogen = 28 g/mole  = $28\times 10^{-3}kg/mol$

Now put all the given values in the above root mean square speed formula, we get:

$\nu_{rms}=\sqrt{\frac{3\times 8.314\times 300}{28\times 10^{-3}}}$

$\nu_{rms}=516.9m/s$

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