Question

Calculate the rms speed of ozone kept in a closed vessel at 20°C and 82cm Hg pressure.

Answer 1

Answer:

3.902 X 10^2 m/s

Explanation:

Vrms = [3RT / Mm] 1/2

R = 8.314 J K-1mol-1

Molar mass of ozone = 48 g / mol = 0.048 Kg / mol

Temperature T = 200 C = 293 K

Therefore V = [(3 X 8.314 X 293) / 0.048] 1/2  

= [15.225 X 10^4] 1/2

= 3.902 X 10^2 m/s