Chemistry, asked by DanteZBuB568, 9 months ago

Calculate the rms velocity of ozone kept in a closed vessel

Answers

Answered by AditiHegde
3

The rms velocity of ozone kept in a closed vessel is 0.3901 m/s

  • Formula for calculating the rms velocity
  • V_{rms}=\sqrt{\dfrac{3RT}{M} }
  • Given,
  • T=20°C=20+273=293 K
  • and
  • 82cm Hg
  • Now,
  • V_{rms}=\sqrt{\dfrac{3 *8.314 *293}{48*10^{-3}} } \\\\V_{rms}=0.3901m/s
Answered by brokendreams
1

The root mean square velocity of ozone  is 39000 cm/s

Explanation:

  • The root mean square velocity is dependent on the absolute temperature of the container and the molecular mass of the gas.
  • The molecular mass of ozone =3 \times16 = 48.
  • The temperature of the gas = 20°C = 293 K.
  • The RMS velocity of the gas = \sqrt{\frac{3RT} {M}.}
  • So the value =
  • \sqrt{\frac{3\times 8.14 \times 10^7 \times 293}{48} }
  • = 39000 cm /s.

For more information about RMS velocity,

https://brainly.in/question/12109643

At certain temperature,the r m s velocity for o2 is 400m/sec.at the same temperature,the r m s velocity for h2 molecules will be?

https://brainly.in/question/6527304

At what temp will the rms velocity of oxygen be one and half times of its value at ntp

Similar questions