Question

Calculate the root mean square velocity of oxygen

molecule at 25 ° ​

Answer 1

Answer:

c=

M

3RT

R=8.314kPa dm

3

K

−1

mol

−1

,T=288 K

and M=0.032 kg mol

−1

Substituting the values in above equation

c=

0.032

3×8.314×288

=473.79 ms

−1

.

Explanation:

c=

M

3RT

R=8.314kPa dm

3

K

−1

mol

−1

,T=288 K

and M=0.032 kg mol

−1

Substituting the values in above equation

c=

0.032

3×8.314×288

=473.79 ms

−1

.

Answer 2

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