Question

calculate the safe compressive load of an hollow cast iron column one end rigidly fixed and the other end hinged of 150mm external diameter,100mm internal diameter and 10m length. use Euler's formula with in factor of safety of 5.take E as 95 G pa.​

Answer 1

Answer:

use this to answer your questions

Explanation:

calculate the safe compressive load of an hollow cast iron column one end rigidly fixed and the other end hinged of 150mm external diameter,100mm internal diameter and 10m length. use Euler's formula with in factor of safety of 5.take E as 95 G pa.​

Answer 2

Safe compressive from Euler's formula is 381.560 KN

Given:

Internal dia = 100 mm

Outer dia = 150 mm

Youngs modulus = 95 Gpa = $95*10^{3} Mpa$

one end fixed one end hinged

FOS = 5

To find

Safe compressive load by Euler's formula

Solution:

We need to find a crippling load

$P=\frac{\pi ^{2}EI }{L^{2} }$      (Here L is the effective length for One end fixed one end hinged = 0.7* original size)

$P=\frac{\pi ^{2}95*10^{3}\frac{\pi }{64} 150^{4}-100^{4} }{(10000*0.7)^{2} }$

   = 381.560 KN

The safe compressive load is 381.560 KN

#SPJ3