Calculate the safe stopping sight distance for design speed of 50kmph for(a) two-way traffic on two lane road (b)two-way traffic on single lane road
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Given: V=50km/hr = 13.9m/s
f=0.37
t= 2.5 sec stopping distance=lag distance + braking distance
SD=vt+v^2/2gf
Stopping Distance = 61.4 m
Stopping sight distance when there are two lanes = stopping distance= 61.4m.
Stopping sight distance for a two way traffic for a single lane = 2[stopping distance]=122.8m
f=0.37
t= 2.5 sec stopping distance=lag distance + braking distance
SD=vt+v^2/2gf
Stopping Distance = 61.4 m
Stopping sight distance when there are two lanes = stopping distance= 61.4m.
Stopping sight distance for a two way traffic for a single lane = 2[stopping distance]=122.8m
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