Question

Calculate the safe stopping sight distance for design speed of 50kmph for(a) two-way traffic on two lane road (b)two-way traffic on single lane road

Answer 1

Given: V=50km/hr = 13.9m/s 

f=0.37 

t= 2.5 sec stopping distance=lag distance + braking distance


SD=vt+v^2/2gf


Stopping Distance = 61.4 m 

Stopping sight distance when there are two lanes = stopping distance= 61.4m. 

Stopping sight distance for a two way traffic for a single lane = 2[stopping distance]=122.8m