Question

Calculate the shortest and the longest wavelengths of the Lyman series. Given, Rydberg constant = 10967700 $m^{-1}$.

Answer 1

In order to calculate the shortest and the longest wavelength of Lyman series we need to use the Rydberg formula.

The shortest wavelength will be the longest line in the Lyman series which is having the highest energy source energy since wavelength and energy are inversely proportional to each other.

Similarly, the longest wavelength of Lyman series will be the shortest line which is having the minimum energy.

The longest wavelength will be the transition from n = 1 to n = 2 and the shortest wavelength will be the transition from n = 1 to n = infinity

Shortest wave length 1/ λ

$=10967700 (\frac{1}{1^2} -\frac{1}{n^2})$

λ$=\frac{9.1}{8\times 10^(-8)}m$

Longest Wavelength,

$=10967700 (\frac{1}{1^2} -\frac{1}{2^2})$

λ$=\frac{4}{3\times 10967700}m$

Answer 2

In order to calculate the shortest and the longest wavelength of Lyman series we need to use the Rydberg formula.

The shortest wavelength will be the longest line in the Lyman series which is having the highest energy source energy since wavelength and energy are inversely proportional to each other.

Similarly, the longest wavelength of Lyman series will be the shortest line which is having the minimum energy.

The longest wavelength will be the transition from n = 1 to n = 2 and the shortest wavelength will be the transition from n = 1 to n = infinity

Shortest wave length 1/ λ

:

Explanation: