Question

Calculate the shortest wavelength on hydrogen spectrum of lymen series

Answer 1

Answer:

d = 911.7 Å

Explanation:

Shortest wavelength --» Largest frequency --» Large energy

So, electron should jump from n = infinity to n=1 (For lyman series) to get the shortest wavelength

Let d = wavelength

$\frac{1}{d} = r( \frac{1}{ {1}^{2} } - \frac{1}{ { \infty }^{2} } )$

d = 1/109678

d = 911.7 Å

Thanks