Calculate the sides of triangle ABC with area 883 cm’and if a: b: c = 15.7:19
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Solution :-
Let us Assume that, side of ∆ABC are 15x , 7x and 19x respectively .
Than, By Heron's formula ,
→ Semi-perimeter of ∆ABC = (15x + 7x + 19x)/2 = 20.5x cm.
So,
→ Area of ∆ABC = √s(s-a)(s-b)(s-c
→ √{20.5x * (20.5x - 15x) * (20.5x - 7x) * (20.5x - 19x)} = 883
→ √{20.5x * 5.5x * 13.5x * 1.5x} = 883
Squaring Both sides ,
→ 20.5x * 5.5x * 13.5x * 1.5x = 883 * 883
→ 2283.1875x⁴ = 883 * 883
→ x⁴ = 341.491445621
→ x ≈ 4.3 cm.
Therefore, Side of ∆ABC :-
→ 15x = 15*4.3 = 64.5 cm.
→ 7x = 7*4.3 = 30.1 cm.
→ 19x = 19*4.3 = 81.7 cm.
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