Question

calculate the simple interest of rupees 1200 at 3 whole 1 by 2% per annum for six months​

Answer 1

Answer:

S I = 21

Step-by-step explanation:

solution ------>

Given:-

• p=1200
• R = 3 1/2% = 7/2%
• N = 6 months

$si = \frac{p \times n \times r}{100} \\ \\ si \: = \frac{1200 \times 7 \times 6}{100 \times 2 \times 12 } \\ \\ si \: = 21$

Answer 2

Step-by-step explanation:

principal=1,200

Rate of Interest=3 whole1/2= 7/2×100

Time=6 months 6÷12= 6/12= 1/2

Simple interest=1,200×7/200×1/2

= 21 Ans

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