Question

calculate the simple interest on rupees ,10,950 from 26 may to 1 September at 12½ % per annum.​

Answer 1

As per the data given in the question,

We have to determine the value of simple interest.

As per question,

It is given that,

Principal = Rs. 10,950

Rate percentage $=12\frac{1}{2}\%$

Time period = from 26 may to 1 September

As here,

The time period is given as the span between 26 may to 1 September, so for exact calculation we will determine the value of time period in days.

So, number of days in may = 6 days (26 may, 27 may, 28 may, 29 may, 30 may and 3 may)

Number of days in June = 30 days

Number of days in July = 31 days

Number of days in August = 31 days

Number of days in September = 1 days ( 1 September)

So, total number of days will be $=(6+30+31+31+1) = 99\:days$

Now converting the days in years,

We will get it as $=\frac{99}{365} \:years$

As we know that,

$SI = \frac{PRT}{100}$

So, putting the values we will get,

$SI = \frac{10950 \times \frac{25}{2} \times \frac{99}{365}}{100}\\=>SI = \frac{10950 \times 25 \times 99}{2 \times 365 \times 100}\\=>SI = Rs. \:371.25$

Hence, the value of interest will be Rs. 371.25.

Answer 2

As per the data given in the question,

In the above question, it is given that,

Given that rupees, 10,950 from 26 may to 1 September at 12½ % per annum.  

Here we have to calculate the simple interest​.

We have to use the formula of simple interest and calculate the days of a given month.

The total numbers of days $=(6+30+31+31+1)=99 \text { days }$

Now in terms of year $\frac{99}{365}$

SI$=\frac{PRT}{100}$

substituting the value in the above equation we get,

$\begin{array}{l}S I=\frac{10950 \times \frac{25}{2} \times \frac{99}{365}}{100} \\S I=\frac{10950 \times 25 \times 99}{2 \times 365 \times 100} \\S I=R s .371 .25\end{array}$

Hence the simple interest of Rs.371.25 on rupees 10950.