Question

calculate the simple interest on rupees 8125 at for 2 years 3 months​

Answer 1

It is given that

Principal (P) = 3125

Rate of interest for continuous = 4%,5% and 6%

Period (n) = 3 years

We know that

Amount = P(1+r/100) n

Substituting the values

=3125(1+4/100)(1+5/100)(1+6/100)

By further calculation

=3125×26/25×21/20×53/50

= 3617.25

Here

CI=A−P

Substituting the values

=3617.25−3125

=492.25

Answer 2

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It is given that

Principal (P) = 3125

Rate of interest for continuous = 4%,5% and 6%

Period (n) = 3 years

We know that

Amount = P(1+r/100) n

Substituting the values

=3125(1+4/100)(1+5/100)(1+6/100)

By further calculation

=3125×26/25×21/20×53/50

= 3617.25

Here

CI=A−P

Substituting the values

=3617.25−3125

=492.25