Question

Calculate the Simple Interest
Rohan borrows ₹1,25,400 from Ravi at the rate of 12.5% p.a. for a period of 9 months. Calculate the total amount he must repay after the duration.

Answer 1

Answer:

S.I.=P×R×T. 1 YEAR =9/12

S.I.= 1,25,400×12.5×9/100×12

S.I.= 1,254×125×3/10×4

S.I.= 470250/40

S.I.=11756.25

A= P+I

A= 1,25,400+11756.25

A=137156.25

Answer 2

 Rs. 1,37,156.25 must repay after the duration

Step-by-step explanation:

Given: Principal;P = Rs 1,25,400

           Rate;R = 12.5% per year

          Time; T : 9 months = $\dfrac{9}{12} =\dfrac{3}{4}$ years

Now as we know

$S.I.=\dfrac{P\times R\times T}{100}$

where S.I. is simple interest , T is time in years , P is principal and R is rate of  interest

Therefore

$S.I. =\dfrac{125400\times 12.5\times \dfrac{3}{4} }{100} \\\\\Rightarrow S.I. =1254\times 12.5\times \dfrac{3}{4} = Rs.11756.25$

Amount must be repay = Principal + S.I.

                                       = Rs. 1,25,400 + Rs. 11756.25= Rs. 1,37,156.25

Hence,  Rs. 1,37,156.25 must repay after the duration

#Learn more

Find the simple interest on Rs. 68,000 at 16(2/3)% per annum for a period of 9 months?

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