Calculate the single electrode potential for cu metal in contact with 0.15M cu2+ solution
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Answer:
We know that, E
red
=E
red
∘
+
n
0.0591
log
10
[ion]
Putting the values of E
red
∘
=0.34 V,n=2 and [Cu
2+
]=0.1M
E
red
=0.34+
2
0.0591
log
10
[0.1]
=0.34+0.02955×(−1)
=0.34−0.02955=0.31045 volt.
Explanation:
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