Calculate the skin depth for the frequency of 1010 Hz for silver. Given that conductivity is
2X107 S/m and µ = 4πX10-7 H/m.
Answers
Answered by
10
Answer:
please mark me brainliest
Answered by
0
Answer:
δ =33542.94μm
Explanation:
given,
- f(frequency) = 1010 Hz
- σ(conductivity)=2X10^7 S/m
- µ = 4πX10^-7 H/m.
to find,
- δ ( skin depth)
solution,
- Formula for calculating the skin depth
- δ = 1/√(πfμσ)
- =1/√(3.14)(10101)(4πX10^-7)(2X10^7)
- =1/√79665.568
- =1/282.25089
- =0.00354294
- =33542.94μm
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