Calculate the slope of the parabola at a point (x, y) obtained by plotting the following function: y=x^2+2x+4
1)2x+2
2) +2x
3)−1.5x
4)0.5
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Answer:
y=x^2+2x+4
y=(x+2)^2
put x=0 we get y=(0+2)^2=4
when x=0,y=4====>(x1,y1)=(0,4)
put x=-2,we get y=(-2+2)^2=0
when x=-2,y=0===>(X2,y2)=(-2,0)
slope of a curve=(y2-y1)/(x2-x1) or (y1-y2)/(x1-x2)
(y2-y1)/(x2-x1)=(0-4)/(-2-0)=-4/-2=-2
slope of the curve is -2
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