Calculate the smallest number such that by adding 26 to it, the result becomes divisible by 28 36 and 45
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First of all we have to find the LCM of these four numbers:
21 = 3 x 7
28 = 2 x 2 x 7
36 = 2 x 2 x 3 x 3
45 = 3 x 3 x 5
LCM = 2 x 2 x 3 x 3 x 5 x 7 = 1260.
Now we have to find the smallest multiple of 1260 which is of five digit.
1260 x 7 = 8820 which is four digit.
1260 x 8 = 10080 which is five digit.
Therefore 10080 is the smallest 5 digit number which is exactly divisible by 21, 28, 36, 45.
Step-by-step explanation:
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