Calculate the solar panel size in Watt, Battery is kWh and charge controller in Watt for the following appliances. Consider Losses are 5% controller losses, 50% battery DoD, 15% battery losses, 25% solar panel losses, solar radiation is 5 kWh/m2/day. Appliances: Bulb (4 Nos. of 40 W running for 5 hours), Fan (2 Nos. of 70 W running for 12 hours), TV (1 No. of 35 W running for 6 hours)
Answers
Answer:
20w
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Answer:
Explanation: Total Load of appliances = Nos of appliances * Power rating of appliance * running hours = (4 * 10 * 5) + (2 * 25 * 12) + (1 * 20 * 6) = 920 Wh / day Total Load = 920 Wh per day Charge controller losses at load side = 5% of 920 Wh = 46 Wh Battery output = 920 + 46 = 966 Wh Battery capacity = Battery output / DOD = 966 / 50% = 966 / 0.5 = 1932 Wh = 1.9 kWh Battery losses = 15% of 966 Wh = 145 Wh Input for Battery = 966 + 145 = 1111 Wh Charge controller losses at panel side = 5% of 1111 Wh = 55.55 Wh Output from solar panel = 1111 + 55.55 = 1166.55 Wh Losses at panel = 25 % of 1166.55 Wh = 291.64 Wh Input at panel = 1166.55 + 291.64 = 1458.19 Wh Solar Radiation = 5 kWh / m2 / day Solar panel requirement = Input at panel / sunshine hours = 1458.19 / 5 = 291.63 W ~ 290 W Size of charge controller = Nos of appliances * Power rating of appliances = (4 * 10) + (2 * 25) + (1 * 20) = 110 W Charge controller capacity should be little higher than the requirement so the capacity can be taken as 120 W.