Calculate the solubility in mol/dm³ of 40g of CuSo4 dissolved in 100g of water at 120°c
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Question:-
Calculate the solubility in mol/dm³ of 40g of CuSo4 dissolved in 100g of water at 120°c?
Answer:-
Mole= mass/molar mass
Molar mass of CuSO4=(64×1)+(32×1)+(16×4)
Molar mass of CuSO4=160g/mol
mole= mass /molar mass
Mole=40g/160g/mol
Mole=0.25mol
0.25mol of CuSO4 was dissolved in 100g of water at 120°C
xmol of CuSO4 dissolved in 1000cm³ of water at 120
x=0.25×1000/100
x=2.50
Answered by
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Solubility= number of moles of solution/volume of solution
100 g of water= 100 cm^3 = 0.1 dm^3
CuSO4= 160g/mol
No. of moles in CuSO4 in 40g = 40/160 = 0.25 mol
Solubility= 0.25/0.1 = 2.5 mol/dm^3
100 g of water= 100 cm^3 = 0.1 dm^3
CuSO4= 160g/mol
No. of moles in CuSO4 in 40g = 40/160 = 0.25 mol
Solubility= 0.25/0.1 = 2.5 mol/dm^3
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