Calculate the solubility of bacro4 and agbr in water at 25c
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Answer:
Ksp =[Ba2+][CrO2−4]
=(1.8×10−5)2
Explanation:
We write the solubility expression in this way:
BaCrO4(s) ⇌Ba^2+ +CrO2−4
Now
Ksp=[Ba^2+] [CrO2−4] =(1.8×10−5)^2
=3.24×10−10.
Why do we square this value? We were quoted the solubility of barium chromate. Because the solubility represents the concentrations of chromate ion and barium ion.
MARK BRAINLIEST
Ksp =[Ba2+][CrO2−4]
=(1.8×10−5)2
Explanation:
We write the solubility expression in this way:
BaCrO4(s) ⇌Ba^2+ +CrO2−4
Now
Ksp=[Ba^2+] [CrO2−4] =(1.8×10−5)^2
=3.24×10−10.
Why do we square this value? We were quoted the solubility of barium chromate. Because the solubility represents the concentrations of chromate ion and barium ion.
MARK BRAINLIEST
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