Question

Calculate the solubility of bacro4 and agbr in water at 25c

Answer 1

Answer:

Ksp =[Ba2+][CrO2−4]

=(1.8×10−5)2

Explanation:

We write the solubility expression in this way:

BaCrO4(s) ⇌Ba^2+ +CrO2−4

Now

Ksp=[Ba^2+] [CrO2−4] =(1.8×10−5)^2

=3.24×10−10.

Why do we square this value? We were quoted the solubility of barium chromate. Because the solubility represents the concentrations of chromate ion and barium ion.

MARK BRAINLIEST