Question

Calculate the solubility product of Al(OH)3 in water:
Al(OH)4 (aq) = ATH(aq) +40H (aq)
K= 1.3x10-34
Al(OH)4 (aq) + Al(OH)3(s) + OH (aq)
K=1/38.5
(1) 3.1 x 10-35
(2) 5 x 10-33
(3) 6.1 x 10-33
(4) None.​

Answer 1

Answer:

Calculate the solubility product of Al(OH)3 in water:

Al(OH)4 (aq) = ATH(aq) +40H (aq)

K= 1.3x10-34

Al(OH)4 (aq) + Al(OH)3(s) + OH (aq)

K=1/38.5

(1) 3.1 x 10-35

(2) 5 x 10-33✔

(3) 6.1 x 10-33

(4) None.