Question

Calculate the specific and molar conductance of a 0.0075m aqueous solution of kcl. given: conductance is 1.49x10-3s and cell constant is 1.05cm-1

Answer 1

× answer of that statement and -the 0.00u5
ok ji you will get your answer
maths work

Answer 2

Answer: Specific conductance=$1.56\times 10^{-3}Scm^{-1}$ and Molar conductance= $208 Scm^2mol^{-1}$

Explanation:

Specific conductance is the conductance for unit volume of a solution

$\kappa=C\times \frac{l}{a}$

where,

$\kappa$ =Specific conductance

C = Conductance =$1.49\times 10^{-3}S$

$\frac{l}{a}$= cell constant =$1.05cm^{-1}$

$\kappa=1.49\times 10^{-3}S\times 1.05cm^{-1}=1.56\times 10^{-3}Scm^{-1}$

Molar conductance is defined as the conductance of all the ions produced by ionization of 1 g mole of an electrolyte when present in V mL of solution.

$\mu=\frac{\kappa\times 1000}{C}$

where,

$\mu$= molar conductance

$\kappa$ =Specific conductance

c = concentration of the solution in mole per litre

$\mu=\frac{1.56\times 10^{-3}Scm^{-1}\times 1000}{0.0075M}=208 Scm^2mol^{-1}$