calculate the specific gravity for 100ml H2SO4 acid solution , if it's 50%pure?
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Explanation:
1000 mL will weigh 1800g
mass of H2 SO4 present = 1800 gm
number of mole of H2 SO 4 = actual mass/molarmass= 1800 ÷ 98 = 18.36
thus molarity of a stock solution is 18.36 M
To prepare 500 mL of 0. 9 M solution, M 1 V 1 =M2 V2
18.36 x A = 0.9 x 500 mL
450/18.36
= 24.5 ml
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