calculate the specific heat capacity of a substance having mass 5 kg.whose temperature increase from 15 degree c to 25 degree c when 19 k j heat is supplied.
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Answer:
1KJ=1000J
19 KJ=19*1000J=19000J
c=mQ/Δt
where c=specific heat capacity,m=mass,Q=Energy ,Δt=change in temperature.
Δt=(25-15) C =10 C
c=(5*19000)/10
c=9500kg J/C
Hope it will help you !!
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