Science, asked by kcdipendra151, 30 days ago

calculate the specific heat capacity of a substance having mass 5 kg.whose temperature increase from 15 degree c to 25 degree c when 19 k j heat is supplied.​

Answers

Answered by Anonymous
0

Answer:

1KJ=1000J

19 KJ=19*1000J=19000J

c=mQ/Δt  

where  c=specific heat capacity,m=mass,Q=Energy ,Δt=change in temperature.

Δt=(25-15) C =10 C

c=(5*19000)/10

c=9500kg J/C

Hope it will help you !!

Explanation:

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