Question

calculate the specific heat capacity of substance having mass 5 kg whose temperature increases from 15 °c to 25°c by the supply of 19kj heat

Answer 1

1KJ=1000J

19 KJ=19*1000J=19000J

c=mQ/Δt  

where  c=specific heat capacity,m=mass,Q=Energy ,Δt=change in temperature.

Δt=(25-15) C =10 C

c=(5*19000)/10

c=9500kg J/C

Hope it will help you !!