Calculate the specific heat capacity of titanium if a 43.56 g sample absorbs 0.476 kJ as its temperature changes from 20.13/C to 41.06/C.
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Answer:
5.22 ×10^-4
Explanation:
using the formula
Q =MCtita
where Q is the quantity of heat
M is the mass of substance
tita is the temperature difference that is t2 -t1 = temp difference
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