Calculate the specific heat of substance of 20 gm using the formula. Weight the calorimeter (m1)with stirrer =25gm Weight of water =80gm. specific heat of copper =0.095. Initial temperature is 20 degree Celsius. Temperature of hot body =60 degree Celsius. Temperature of the mixture =40 degree Celsius
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now..
the heat loss of the substance = heat gain by the water + heat gain by the calorimeter
heat loss if the substance = (m2)(C2)( Θfinal - Θinitial )
Θfinal = final temperature of the substance/mixture
Θinitial = inital temprature of the subtance
m2 = mass of thesubstance
C2 = specific heat capacity of the subtance
in the same manner...
heat gain by the water = (m3) (Cw)( Θfinal - Θinitial )
heat gain by the calorimeter = (m1)(Cc)( Θfinal - Θinitial )
hope this will help you :)
the heat loss of the substance = heat gain by the water + heat gain by the calorimeter
heat loss if the substance = (m2)(C2)( Θfinal - Θinitial )
Θfinal = final temperature of the substance/mixture
Θinitial = inital temprature of the subtance
m2 = mass of thesubstance
C2 = specific heat capacity of the subtance
in the same manner...
heat gain by the water = (m3) (Cw)( Θfinal - Θinitial )
heat gain by the calorimeter = (m1)(Cc)( Θfinal - Θinitial )
hope this will help you :)
AcHyUtHrAm:
this is very helpful for me
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