Question

calculate the specific weight and density and specific gravity of 1 litre of a liquid which has the weight of 7 N
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Answer 1

Answer:

Below!

Explanation:

specific weight = density x g

density = mass/volume

7N force = mass x g

mass = 0.7 kg  (taking g = 10 ms-2)

density = 0.7/1

            = 0.7 kg/l

specific weight = 0.7 x 10 = 7 N/m3

Answer 2

Answer:

Weight = 7 N.

To find,

Specific gravity,

Density.

Solution

The specific gravity of a liquid is defined as the ratio of the density of a liquid to the density of the reference substance, that is water in the case of liquids. It is given by,

SG = pLiquid/pH₂O   ...(1)

where,

SG = specific gravity of the liquid,

pLiquid,pH₂O  are the densities of the liquid and water respectively.

The density is defined as mass per unit volume of a liquid or substance, and is given by,

Density = Mass/Volume   ...(2)

Here, the given volume is 1 L, and 1 L = 0.001 m³. So,

V = 0.001 m³.

The weight is given as 7 N. Since,

Weight= m×g

m = W/g

= 7/9.8

⇒ m = 0.714 kg

Now, from eq. (2),

p =m/V

= 0.714/0.001

⇒ ρ = 714 kg/m³.

Using the above-calculated value of density and eq. (1), for specific gravity,

As  pH₂O = 1000 kg/m³

SG = 714/1000

⇒ SG = 0.714.

Therefore, the specific gravity of the given liquid is 0.714, and its density is 714 kg/m³.

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