Question

Calculate the speed and period of revolution of a satellite orbiting at a height of 700km above the earth's surface?

Answer 1

centrifugal acceleration

centrifugal acceleration  

From the relationship  

Fcentripetal = Fcentrifugal centripetal force = centrifugal force  

We note that the mass of the satellite, ms, appears on both sides, geostationary orbit is independent of the mass of the satellite.  

Image

Image  

r (Orbital radius) = Earth's equatorial radius + Height of the satellite above the Earth surface  

r = 6,378 km + 35,780 km

r = 42,158 km

r = 4.2158 x 107 m  

Image

Speed of the satellite  

Speed of the satellite is 3.0754 x 103 m/s