Question

Calculate the speed of a 5.2 kg object that possesses 26.1 J of kinetic energy​

Answer 1

Answer:

3.61m/s

Explanation:

KE= $1/2mv^2$

26.1=1/2×5.2×$v^2$

$v^2$=26.1×2/5.2

v= 3.61m/s         [approx]

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Answer 2

Answer:

KE= 1/2mv^21/2mv 2

26.1=1/2×5.2×v^2v 2

v^2v 2

=26.1×2/5.2

v= 3.61m/s

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