Question

Calculate the speed of an artificial spaceship which is orbiting at a height of 8000 kilometres above the surface of the earth. Take mass of the earth is equal to 6* 10 24 kg. Radius of the earth is equal to 6400 kilometres and gravitational constant is equal to 6.67 * 10 Newton metre square by kg square. -11​

Answer 1

Answer:

v

e

=

R

2GM

=

6400×10

3

2×6.67×10

−11

×6×10

24

=11183.13ms

−1

K.E=

2

1

mv

e

2

=

2

1

(1000)×(11183.1300)=5591567.3J

Answer 2

Answer:

= 9.80m/s2

A 60.0 kg mass is located 1500 km above the surface of the Earth. The acceleration due to gravity on the Earth's surface is g= 9.80m/s2 and the radius of Earth is 6.37 x 106 m

Explanation:

please make as thanks