Question

calculate the speed of an electron‚ if it possesses 60 eV energy.​

Answer 1

Hi friend here is your answer.

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K.E.=1/2mv^2

60ev=1/2 ×mass of e ×v^2 ans.

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Answer 2

Given :

Energy possess by the electron , $E=60\ eV$ .

To Find :

The speed of electron .

Solution :

Converting energy in eV to Joule .

$E=60\times 1.6\times 10^{-19}\ J\\E=9.6\times 10^{-18}\ J$

We know , kinetic energy is given by :

$E=\dfrac{mv^2}{2}$

Therefore , $v=\sqrt{\dfrac{2E}{m}}$        ....( 1 )

Here , m is mass of electron and equal to $m=9.1\times 10^{-31}\ kg$ .

Putting value of E and m in equation 1 .

We get ,

$v=\sqrt{\dfrac{2\times 9.6\times 10^{-18}}{9.1\times 10^{-31}}}\\\\v=4.59\times 10^6\ m/s$

Therefore , the speed of an electron is $4.59\times 10^6\ m/s$ .

Learn More :

Kinetic Energy

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