Calculate the speed of electron revolving around the nucleus of a hydrogen atom in order that it may not be pulled into the nucleus by electrostatic attraction
Answers
Answered by
4
Answer:
see equate the centrfugalal force and the electrostatic force of attraction kze^2/r^2=mv^2/r
and also
mvr=nh/2pie (angilarmomentum)
and divide these two equations and u)( get the speed directly
thanks
Answered by
2
The value of velocity is equal to 4πke²/nh
First we will equate the centrifugal force equation and the electrostatic force of attraction equation-
kze²/r² = 1/2 mv²/r
=> 2kze²/r = mv² -------(1)
The angular momentum of the electron in the nth orbital of the hydrogen atom,mvr = nh/2π
=> r = nh/2πmv
Put the value of r in the equation (1)
=> 2kze²/(nh/2πmv) = mv²
=> 2kze²×2πmv / nh = mv²
=> 4πkze²/nh = v
=> v = 4πke²/nh [z = 1 , for hydrogen atom]
The value of v is equal to 4πke²/nh
Similar questions