Question

calculate the speed of light in a medium whose critical angle 30°​

Answer 1

n= 1/sinC = 1/sin30º = 2 Speed of light in medium v = c/n = (3 x108)/2 = 1.5 x 108m/s = 1.5 x 108m/s

hope it will help you friend ✌️✌️✨

Answer 2

Answer:

1.5×10^8m/s

Explanation:

Here, v=?,C=30∘

μ=Cv=1sinC

v=csinC=3×108×sin30∘=1.5×10^8m/s