Question

Calculate the speed of light in a medium whose critical angle is
${45}^{o}$
?

Answer 1

n= 1/sinC = 1/sin45° = √2 

Therefore speed of light in vaccum = speed of light in air/n = 3×10^8/1.414 = 2.121×10^8 m/s

Answer 2

Answer:

Step-by-step explanation:

Refractive index=1/sin(Critical angle)=1/sin45=✓2

Refractive index=Speed of light in air/Speed of light in medium

So, required speed is (3*10^8)/✓2 m/s

Hope you understood