Question

Calculate the speed of light in glycerine if its index of re- fraction is 1.47.​

Answer 1

Answer:

$2.041.10^{8} ms^{-1}$

Explanation:

v=c/n

refractive index of air  =1.005 ≈ 1

n- refractive index of glycerine = 1.47

c- velocity of light in air = $3*10^8 m/s^$

v-velocity of light in glycerine = ???

Using equation - v=c/n

velocity of light in glycerine=(3x $10^8$)/1.47 ≈ $2.041.10^{8} m/s$(Approx.)

(Above answer is only approximate original answer will be too long with decimals I'm giving it below)

velocity of light in glycerine=2.040816327 x $10^8$$m/s$ =204081632.7$m/s$

Answer 2

Answer:

The speed of light in glycerine is 2.14×$10^8$m/s

Explanation:

Refractive index is given by,

μ= $\frac{C}{V}$

Where,

μ= refractive index

C = speed of light.

V = speed of the medium

The Refractive index of glycine is given by,

μ=1.4

Use the formula of refractive index,

μ= $\frac{C}{V}$

Put values

1.4=3×$10^8$ / V

V=2.14×$10^8$m/s

The speed of light in glycerine is V=2.14×$10^8$m/s.

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