Physics, asked by esmasyed358, 11 months ago

Calculate the speed of the second hand of a watch of length 1.5 cm please elaborate.

Answers

Answered by Habibqureshi
1

Answer:

Seconds HAND of watch completes 1 revolution in 60 sec ( 1min).

Time = t=60 sec

The length of seconds HAND of watch will be it's radius

r=1.5cm =1.5/100=0.015 m

DISTANCE covered = 2 * pi* r

= 2* 3.14 *0.015

Speed = distance/ time

= 2*3.14*0.015/60

=0.00157 m/ s

= 1.57 x 10 ^-3 m/s.

Therefore , speed of the tip of second's hand of a watch of length 1.5 cm is 1.57 x 10 ^-3 m/s.

Please make my answer Brainlist.

Answered by amitkhokhar
1

π /30 radians per second

π/ 20 cm per second

2π radians per minute = π/30 radians per second

(π/30)×1.5 = π/20 m/s

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