Physics, asked by ishasharvani2007, 9 months ago

calculate the speed of the tip of seconds hand of a watch of 1.5cm

Answers

Answered by ashoknehra995
0

Answer:

The Speed is 5 km an hour

Answered by Anonymous
1

\huge\mathbb{\red A \pink{N} \purple{S} \blue{W} \orange{ER}}

time period T = 60 seconds

Angular velocity ? = 2p/T = 2× 3.14/60 = 0.105 radian/sec

Length of the second's hand R = 1.5 cm

                                                = 0.015 m

Therefore, radial velocity of the second's hand

V= Rw

or, v = 0.015 × 0.105 m/s

       = 1.57 × 10?³ m/s

Similar questions