calculate the speed of the tip of seconds hand of a watch of 1.5cm
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Answer:
The Speed is 5 km an hour
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time period T = 60 seconds
Angular velocity ? = 2p/T = 2× 3.14/60 = 0.105 radian/sec
Length of the second's hand R = 1.5 cm
= 0.015 m
Therefore, radial velocity of the second's hand
V= Rw
or, v = 0.015 × 0.105 m/s
= 1.57 × 10?³ m/s
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