Question

Calculate the 'spin only' magnetic moment of Mag ion (Z = 27).

Answer 1

Explanation:

Given ion is M²+ with the atomic no.27.

so, electronic configuration of M²+ is [Ar]

3d⁷4s⁰

[Ar] ↿⇂ ↿ ⇂ ↿ ↿ ↿

3d. 4s

No. of unpaired e– s=3

So, the spin only magnetic moment is given by,

μ= √n+n+2) = √ 3(3+2) = √3 x 5 = √15 BM

= 3.87 BM

Hope this helps you...☺️

Answer 2

Answer:

∴Spin only magnetic moment (μ)=√n(n+2) B.M. =√3(3+2)=√15 B.M. =3.87B.M.

Explanation:

Given ion is M2+ with the atomic no. 27.

So, electronic configuration of M2+ is  [Ar] 3d74s0

[Ar]  ↿⇂   ↿ ⇂  ↿   ↿   ↿    

              3d                               4s 

No. of unpaired e− s =3

So, the spin only magnetic moment is given by,

μ=n(n+2)       =3(3+2)  =3X5 =15 BM

=3.87 BM