Chemistry, asked by Jemilna123, 5 hours ago

Calculate the spin only magnetic moment of Ni2+ and Fe3+ ions

Answers

Answered by avanishyadav16

3

Answer:

Correct option is

D

6

26

Fe=[Ar]3d

6

4s

2

Fe

3+

=[Ar]3d

5

Number of unpaired electrons =5

μ=

n(n+2)

μ=

5×(5+2)

μ=

35

=5.91BM

μ=6BM

Answered by cjha33976

0

Answer:

26

Fe=[Ar]3d

6

4s

2

Fe

3+

=[Ar]3d

5

Number of unpaired electrons =5

μ=

n(n+2)

μ=

5×(5+2)

μ=

35

=5.91BM

μ=6BM

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