Question

Calculate the standard cell potential for fe2++ag+

Answer 1

Eø Fe3+ / Fe2+  =  0.77 V

   Eø Ag+ / Ag        =  0.80 V

The galvanic cell of the given reaction is depicted as:



Now, the standard cell potential is

Eø  = EøR  - EøL

       = 0.80 - 0.77

     = 0.03 L

Here, n = 1.

Then, ΔrGø = -nFEøcell

= - 1 × 96487 C mol - 1 × 0.03 V

= - 2894.61 J mol - 1

= - 2.89 kJ mol - 1

Again, ΔrGø = - 2.303 RT ln K



= 0.5073

K = antilog (0.5073)

= 3.2 (approximately)