Question

Calculate the standard enthalpy of formation of CH 3 OH(l) from the
following data:
CH 3 OH (l) + 3/2 O 2 (g) → CO 2 (g) +H 2 O(l) ∆H = -726kj
C(g) + O 2 (g) → CO 2 (g) ∆H = -393 KJ
H 2 (g) + ½ O 2 (g) → H 2 O (L) ∆H = -298 KJ …………..(3)

Answer 1

Answer:

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Explanation:

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