calculate the standard free energy change for a reaction at 298 k ,if its equilibrium
constant is 50
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1) T = 25 + 273 = 298 K. To determine the change in the number of moles of gas, take the number of moles of gaseous products and subtract the number of moles of gaseous reactants. ...
2) Δn = 2 − 4 = −2 mol. Note that Δn is negative. ...
3) K P = (4.2 × 10 −2)(0.08205)(298) −2 Solving,
4) K P = 7.0 × 10 −5
Explanation:
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