Chemistry, asked by sakshamn396, 9 months ago

Calculate the standard gibbs energy for the given cell reaction in kj molâ1molâ1at 298 k is:zn(s)+cu2+(aq)âzn2+(aq)+cu(s),zn(s)+cu2+(aq)âzn2+(aq)+cu(s),eâ=2vat298keâ=2vat298k(faraday's constant,f=96000cmolâ1f=96000cmolâ1)

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Answered by rohit3983

2

Answer:

please try different words in the question

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