Question

Calculate the stopping distance of a car travelling with
a speed of 72 km/h and being accelerated with
a - 5 m/ sec.​

Answer 1

Answer:

40m

Step-by-step explanation:

Here, u = 72 km/h = (72 × 5/18)m/s = 20 m/s

v = 0 m/s

a = -5 m/s²

S = ? m

We know, v² = u² + 2aS

=> (0)² = (20)² + 2 × (-5) × S

=> 10S = 400

=> S = 400/10 m = 40m

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