Calculate the stopping sight distance on a highway ata a descending gradient of 4% for a design speed of 60 kmph. Assume reaction time of driver 2.5 secs and co-efficient of friction between tyre and road surface=0.4.
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Answer:
Descending gradient = 2%
V = 80 kmph = 22.22 m/sec
SSD=Vt+V22g(f−π100)....-ve for descending gradient=22.22×2.5+22.2222×9.81(0.35−0.2100)=127.86m≈128m
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Answer:
Descending gradient = 2%
V = 80 kmph = 22.22 m/sec
SSD=Vt+V22g(f−π100)....-ve for descending gradient=22.22×2.5+22.2222×9.81(0.35−0.2100)=127.86m≈128m
Explanation:
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