Physics, asked by dhanyasharma2005, 1 month ago

Calculate the strength and molarity of a solution containing 15 g of KMnO4 in 200 ml of the solution . Also find out the the molarity of the resultant solution prepared by adding 400 ml water to this solution .​

Answers

Answered by ay8076191
0

Explanation:

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Concentrations may be quantitatively assessed using a wide variety of measurement units, each convenient for particular applications. Molarity (M) is a useful concentration unit for many applications in chemistry. Molarity is defined as the number of moles of solute in exactly 1 liter (1 L) of the solution:

M

=

mol solute

L solution

M=mol soluteL solution

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Answered by Anonymous
1

Answer:

Molarity = moles of solute / Volume of solution in litre

Explanation:

moles of solute = 15 / 158

volumes = 200/1000

M = 15/158 ÷ 200 / 1000

= 15 / 158 × 1000 / 200

= 0.47 M

M1 × V1 = M2 × V2

0.47 × 200 = M2 × 400

94/400 = M2 ( resultant molarity )

M2 = 0.235 M

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